Detay
- Meslek
- webmaster
Kodları kopyalayın index.php dosyayı aç yapıştırın.
Kod:
<?php
/*
### Instagram Profil Fotoğrafı Görüntüleyici
### Coded by erjantr@gmail.com
### http://instagr.am/erjantr
### Web Developer and Graphic Designer
*/
date_default_timezone_set('Europe/Istanbul');
$getUrl = $_SERVER['REQUEST_URI'];
class myApp {
private function getUserId($userName){
$getHtml = file_get_contents('https://instagram.com/'.$userName);
$getData = substr($getHtml, strpos($getHtml, 'window._sharedData'), strpos($getHtml, '};'));
$userId = strstr($getData, '"id":"');
$userId = str_replace('"id":"', '', $userId);
$userId = strstr($userId, '"', true);
return $userId;
}
public function getBigProfile($userName){
$userId = $this->getUserId($userName);
$getJson = file_get_contents('https://i.instagram.com/api/v1/users/' . $userId . '/info/');
$getData = json_decode($getJson, true);
$resultData = array('status' => 'ok', 'hd_profile_pic_url' => $getData['user']['hd_profile_pic_url_info']['url']);
return json_encode($resultData);
}
}
if(isset($_POST['userName'])){
header('Content-Type: application/json');
$myApp = new myApp;
echo $myApp->getBigProfile($_POST['userName']);
}else{
?>
<html>
<body>
<head>
<script src="https://code.jquery.com/jquery-3.2.1.js" type="text/javascript"></script>
<script>
function getProfilePicture(){
userName = $("#userName").val();
$.ajax({
type: "POST",
url: "<?=$getUrl?>",
data: {userName:userName},
dataType: "json",
beforeSend: function(){
$("#pageLoading").html('Yükleniyor...');
},
success: function(data){
$("#pageLoading").html('Başarılı...');
profilePicUrl = data.hd_profile_pic_url;
$("#pageResult").html('<img src="'+profilePicUrl+'">');
},
error: function(){
$("#pageLoading").html('Bir sorun oluştu...');
}
});
}
</script>
</head>
<input type="text" id="userName" placeholder="Kullanıcı adı">
<button type="button" onclick="getProfilePicture()">Gönder</button>
<div id="pageLoading"></div>
<div id="pageResult"></div>
</body>
</html>
<?php } ?>
